Physics Circle home Student Login

Home›Chapters›Viscosity PYQs›Viscosity & Stokes' Law›Question 23

MHT CET 2021 (22 Sep, Shift 2) · Viscosity & Stokes' Law

Viscosity & Stokes' Law question from MHT CET 2021 (22 Sep, Shift 2)

Q23MHT CET 2021 · 22 SEP · SHIFT 2Medium

Viscosity & Stokes' Law

A ball rises to the surface of a liquid with constant velocity. The density of the liquid is four times the density of the material of the ball. The viscous force of the liquid on the rising ball is greater than the weight of the ball by a factor of

Show answer and solution

Answer: (b)

  1. Rising at constant velocity: B=W+FB = W + F, with B=V(4ρ)g=4WB = V(4\rho)g = 4W.
  2. F=4W−W=3WF = 4W - W = 3W
  3. So the viscous force is 33 times the weight: answer (b) 3.
Report a mistake

More questions on Viscosity & Stokes' Law