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NEET 2003 (AIPMT) · Rolling Motion

Rolling Motion question from NEET 2003 (AIPMT)

Q87NEET 2003 · AIPMTMedium

Rolling Motion

A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is K. If radius of the ball be R. then the fraction of total energy associated with its rotational energy will be

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Answer: (c)

$KE_{rot} = \frac{1}{2}mK^2\omega^2$ and $KE_{tr} = \frac{1}{2}mv^2 = \frac{1}{2}mR^2\omega^2$ .
Fraction $= \dfrac{K^2}{K^2 + R^2}$ .
So the answer is (c).

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