A balloon is filled at 27 and 1 atmospheric pressure by volume 500 m³ helium gas. At -3 and 0.5 atmospheric pressure, the volume of helium gas will be (a) 500 m³ (b) 700 m³ (c) 900 m³ (d) 1000 m³

Answer: (c). Gas equation: (P₁V₁)/(T₁) = (P₂V₂)/(T₂), with T₁ = 300 K, T₂ = 270 K. V₂ = 500 × 1/0.5 × (270)/(300) = 900 m ³ So the answer is (c) 900 m ³.

A balloon is filled at 27 and 1 atmospheric pressure by volume 500 m³… | MHT CET 2025 (25 Apr, Shift 2)

Q17MHT CET 2025 · 25 APR · SHIFT 2Easy

Gas Laws & Ideal Gas Equation

A balloon is filled at $27^\circ\text{C}$ and 1 atmospheric pressure by volume $500\text{ m}^{3}$ helium gas. At $-3^\circ\text{C}$ and 0.5 atmospheric pressure, the volume of helium gas will be

Show answer and solution

Answer: (c)

Gas equation: $\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}$ , with $T_1 = 300$ K, $T_2 = 270$ K.
$V_2 = 500 \times \dfrac{1}{0.5} \times \dfrac{270}{300} = 900$ m $^3$
So the answer is (c) $900$ m $^3$ .

Report a mistake

Gas Laws & Ideal Gas Equation question from MHT CET 2025 (25 Apr, Shift 2)

More questions on Gas Laws & Ideal Gas Equation