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JEE Main 2021 (25 Jul, Shift 2) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2021 (25 Jul, Shift 2)

Q37JEE Main 2021 · 25 JUL · SHIFT 2Medium

Motion Under Gravity

A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around:

(take the value of g as 10 m/s2)

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Answer: (c)

  1. Object starts with 10 m/s10\text{ m/s} upward from 75 m.
  2. −75=10t−5t2⇒t=5 s-75 = 10t - 5t^2 \Rightarrow t = 5\text{ s}
  3. Balloon height =75+10(5)=125 m= 75 + 10(5) = 125\text{ m}
  4. So the answer is (c) 125 m.
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