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NEET 2014 (AIPMT) · Apparent Weight & Lift

Apparent Weight & Lift question from NEET 2014 (AIPMT)

Q16NEET 2014 · AIPMTMedium

Apparent Weight & Lift

A balloon with mass m is descending down with an acceleration a (where a < g). How much mass should be removed from it so that it starts moving up with an acceleration a?

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Answer: (a)

  1. Descending with aa: mg−U=ma⇒U=m(g−a)mg - U = ma \Rightarrow U = m(g - a), where UU is the upthrust (unchanged).
  2. After removing Δm\Delta m, rising with aa: U−(m−Δm)g=(m−Δm)a⇒m−Δm=m(g−a)g+aU - (m - \Delta m)g = (m - \Delta m)a \Rightarrow m - \Delta m = \dfrac{m(g - a)}{g + a}.
  3. Δm=m−m(g−a)g+a=2mag+a\Delta m = m - \dfrac{m(g-a)}{g+a} = \dfrac{2ma}{g + a}
  4. So the answer is (a) 2mag+a\dfrac{2ma}{g+a}.
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