A bar magnet with a magnetic moment 5.0 Am² is placed in parallel position relative to a magnetic field of 0.4 T. The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is _____________. (a) zero (b) 1 J (c) 2 J (d) 4 J

Answer: (d). Parallel to antiparallel: W = MB(cos 0° - cos 180°) = 2MB. W = 2 × 5.0 × 0.4 = 4 J So the answer is (d) 4 J.

A bar magnet with a magnetic moment 5.0 Am² is placed in parallel… | JEE Main 2023 (31 Jan, Shift 1)

Q10JEE Main 2023 · 31 JAN · SHIFT 1Easy

Field of a Magnet & Magnet in a Uniform Field

A bar magnet with a magnetic moment $5.0\text{ Am}^2$ is placed in parallel position relative to a magnetic field of $0.4\text{ T}$ . The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is _____________.

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Answer: (d)

Parallel to antiparallel: $W = MB(\cos 0^\circ - \cos 180^\circ) = 2MB$ .
$W = 2 \times 5.0 \times 0.4 = 4\ \text{J}$
So the answer is (d) 4 J.

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