Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Cells: EMF, Internal Resistance & Combinations›Question 31

JEE Main 2020 (4 Sep, Shift 1) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2020 (4 Sep, Shift 1)

Q31JEE Main 2020 · 4 SEP · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is:

Show answer and solution

Answer: (c)

  1. Power in load P=VI⇒I=0.52.5=0.2 AP = VI \Rightarrow I = \dfrac{0.5}{2.5} = 0.2\text{ A}.
  2. Drop across internal resistance =E−V=3.0−2.5=0.5 V= E - V = 3.0 - 2.5 = 0.5\text{ V}.
  3. Pint=0.5×0.2=0.10 WP_{int} = 0.5 \times 0.2 = 0.10\text{ W}
  4. So the answer is (c) 0.10 W.
Report a mistake

More questions on Cells: EMF, Internal Resistance & Combinations