A battery of 6 V is connected to the ends of uniform wire 3 m long and of resistance 100 Ω. The difference of potential between two points 50 cm apart on the wire is (a) 1 V (b) 1.5 V (c) 2 V (d) 3 V

Answer: (a). k = V/L = 6/3 = 2 V/m (resistance value is not needed). V = k l = 2 × 0.5 = 1 V. So the answer is (a) 1 V.

A battery of 6 V is connected to the ends of uniform wire 3 m long… | MHT CET 2024 (11 May, Shift 2)

Q31MHT CET 2024 · 11 MAY · SHIFT 2Easy

Potentiometer

A battery of 6 V is connected to the ends of uniform wire 3 m long and of resistance $100\ \Omega$ . The difference of potential between two points 50 cm apart on the wire is

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Answer: (a)

$k = \frac{V}{L} = \frac{6}{3} = 2\ \text{V/m}$ (resistance value is not needed).
$V = k l = 2 \times 0.5 = 1\ \text{V}$ .
So the answer is (a) 1 V.

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Potentiometer question from MHT CET 2024 (11 May, Shift 2)

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