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JEE Main 2020 (7 Jan, Shift 1) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2020 (7 Jan, Shift 1)

Q60JEE Main 2020 · 7 JAN · SHIFT 1Difficult

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

A beam of electromagnetic radiation of intensity 6.4 × 10–5 W/cm2 is comprised of wavelength, λ\lambda = 310 nm. It falls normally on a metal (work function ϕ\phi = 2eV) of surface area of 1 cm2. If one in 103 photons ejects an electron, total number of electrons ejected in 1 s is 10x. (hc = 1240 eVnm, 1eV = 1.6 × 10–19 J), then x is _____.

Numerical answer type. Work it out, then open the answer.

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Answer: 11

  1. Power on 1 cm2^2: P=6.4×10−5P = 6.4\times10^{-5} W.
  2. Photon energy E=1240310=4E = \dfrac{1240}{310} = 4 eV =6.4×10−19= 6.4\times10^{-19} J (greater than ϕ\phi, so emission occurs).
  3. Photons per second =6.4×10−56.4×10−19=1014= \dfrac{6.4\times10^{-5}}{6.4\times10^{-19}} = 10^{14}.
  4. Electrons per second =1014103=1011= \dfrac{10^{14}}{10^{3}} = 10^{11}, so x=11x = 11.
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