A beam of unpolarized light passes through a tourmaline crystal A and… | MHT CET 2023 (9 May, Shift 1)

Q33MHT CET 2023 · 9 MAY · SHIFT 1Easy

Polarisation

A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second tourmaline crystal B oriented so that its principal plane is parallel to that of A. The intensity of emergent light is $I_0$ . Now B is rotated by $45^\circ$ about the ray. The emergent light will have intensity $\left(\cos 45^\circ = \frac{1}{\sqrt{2}}\right)$

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Answer: (a)

With A and B parallel, the light leaving B has intensity $I_0$ (polarised along A).
After rotating B by $45^\circ$ , Malus's law: $I = I_0\cos^2 45^\circ$
$I = I_0 \times \dfrac{1}{2} = \dfrac{I_0}{2}$
So the answer is (a) $\dfrac{I_0}{2}$ .

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Polarisation question from MHT CET 2023 (9 May, Shift 1)

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