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MHT CET 2021 (21 Sep, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2021 (21 Sep, Shift 2)

Q43MHT CET 2021 · 21 SEP · SHIFT 2Easy

Excess Pressure: Drops & Bubbles

A big water drop is divided into 8 equal droplets. ΔPs\Delta P_s and ΔPB\Delta P_B be the excess pressure inside a smaller and bigger drop respectively. The relation between ΔPs\Delta P_s and ΔPB\Delta P_B is

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Answer: (b)

  1. Volume conserved: R3=8r3⇒R=2rR^3 = 8r^3 \Rightarrow R = 2r.
  2. ΔP=2TR∝1R\Delta P = \frac{2T}{R} \propto \frac{1}{R}, so ΔPBΔPS=rR=12\frac{\Delta P_B}{\Delta P_S} = \frac{r}{R} = \frac{1}{2}.
  3. So the answer is (b) ΔPB=12ΔPS\Delta P_B = \frac{1}{2}\Delta P_S.
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