A black body emits radiation of maximum intensity of wavelength ' λ ' at temperature 'T' K. Its corresponding wavelength at temperature (2.5T) K will be (a) (2λ)/(3) (b) (2λ)/(5) (c) (4λ)/(5) (d) (16λ)/(81)

Answer: (b). Wien's law: λm ∝ 1/T. λ' = λ T/2.5T = (λ)/(2.5) = (2λ)/(5) So the answer is (b) (2λ)/(5).

A black body emits radiation of maximum intensity of wavelength ' λ '… | MHT CET 2026 (17 Apr, Shift 2)

Q12MHT CET 2026 · 17 APR · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

A black body emits radiation of maximum intensity of wavelength ' $\lambda$ ' at temperature 'T' K. Its corresponding wavelength at temperature $(2.5T)$ K will be

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Answer: (b)

Wien's law: $\lambda_m \propto \dfrac{1}{T}$ .
$\lambda' = \lambda \dfrac{T}{2.5T} = \dfrac{\lambda}{2.5} = \dfrac{2\lambda}{5}$
So the answer is (b) $\dfrac{2\lambda}{5}$ .

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Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (17 Apr, Shift 2)

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