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MHT CET 2021 (21 Sep, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2021 (21 Sep, Shift 1)

Q91MHT CET 2021 · 21 SEP · SHIFT 1Easy

Thermal Radiation: Black Body, Stefan & Wien

A black body has maximum wavelength 'λm\lambda_{m}' at temperature 2000 K2000\text{ K}. Its corresponding wavelength at temperature 3000 K3000\text{ K} will be

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Answer: (b)

  1. Wien's law: λmT=\lambda_m T = constant.
  2. λ′=λm×20003000=2λm3\lambda' = \lambda_m \times \dfrac{2000}{3000} = \dfrac{2\lambda_m}{3}
  3. So the answer is (b) 2λm3\dfrac{2\lambda_m}{3}.
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