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MHT CET 2025 (5 May, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2025 (5 May, Shift 2)

Q43MHT CET 2025 · 5 MAY · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

A black body has maximum wavelength ' λm\lambda_{m} ' at temperature 2000 K. Its maximum wavelength at 3000 K will be

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Answer: (d)

  1. Wien's law: λmT=\lambda_m T = constant.
  2. λ′=λm×20003000=23λm\lambda' = \lambda_m \times \dfrac{2000}{3000} = \dfrac{2}{3}\lambda_m
  3. So the answer is (d) 23λm\dfrac{2}{3}\lambda_m.
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