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MHT CET 2026 (19 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (19 Apr, Shift 1)

Q7MHT CET 2026 · 19 APR · SHIFT 1Easy

Thermal Radiation: Black Body, Stefan & Wien

A black body is at temperature 827∘827^\circC. The rate at which it emits energy is proportional to

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Answer: (c)

  1. Stefan's law uses absolute temperature: T=827+273=1100T = 827 + 273 = 1100 K
  2. E∝T4=(1100)4E \propto T^4 = (1100)^4
  3. So the answer is (c).
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