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MHT CET 2023 (10 May, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2023 (10 May, Shift 2)

Q83MHT CET 2023 · 10 MAY · SHIFT 2Medium

Thermal Radiation: Black Body, Stefan & Wien

A black body radiates maximum energy at wavelength 'λ\lambda' and its emissive power is 'E' Now due to change in temperature of that body, it radiates maximum energy at wavelength 2λ3\frac{2\lambda}{3}. At that temperature emissive power is

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Answer: (a)

  1. Wien: λm→2λ3\lambda_m \to \frac{2\lambda}{3} means T→32TT \to \frac{3}{2}T.
  2. Stefan: E∝T4⇒E′=(32)4E=8116EE \propto T^4 \Rightarrow E' = \left(\frac{3}{2}\right)^4 E = \frac{81}{16}E
  3. So the answer is (a) 8116\frac{81}{16} (times EE).
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