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MHT CET 2026 (15 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (15 Apr, Shift 1)

Q36MHT CET 2026 · 15 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

A black disc has a radius 'R' and wavelength corresponding to the maximum intensity is 'λ\lambda'. The emissive power (E) for the different radii and maximum wavelengths is directly proportional to

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Answer: (b)

  1. Power from the disc: E=σAT4E = \sigma A T^4 with A∝R2A \propto R^2.
  2. Wien: T=bλ⇒T4∝λ−4T = \frac{b}{\lambda} \Rightarrow T^4 \propto \lambda^{-4}.
  3. E∝R2λ−4E \propto R^2 \lambda^{-4}, so the answer is (b).
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