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NEET 2014 (AIPMT) · Escape Velocity

Escape Velocity question from NEET 2014 (AIPMT)

Q69NEET 2014 · AIPMTMedium

Escape Velocity

A black hole is an object whose gravitational field is so strong that even light cannot escape from it. To what approximate radius would earth (mass = 5.98 ×\times 1024 kg) have to be compressed to be a black hole?

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Answer: (c)

  1. Black hole: escape speed equals cc, so 2GMR=c⇒R=2GMc2\sqrt{\frac{2GM}{R}} = c \Rightarrow R = \frac{2GM}{c^2}.
  2. R=2×6.67×10−11×5.98×1024(3×108)2=7.98×10149×1016R = \frac{2\times 6.67\times10^{-11}\times 5.98\times10^{24}}{(3\times10^{8})^2} = \frac{7.98\times10^{14}}{9\times10^{16}}.
  3. R≈8.9×10−3 m≈10−2 mR \approx 8.9\times10^{-3}\text{ m} \approx 10^{-2}\text{ m}.
  4. So the answer is (c) 10−210^{-2} m.
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