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MHT CET 2026 (13 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (13 Apr, Shift 1)

Q30MHT CET 2026 · 13 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

A black rectangular surface of area A emits energy E per unit time at 27∘27^\circ C. If length and breadth is reduced to (14)th\left(\frac{1}{4}\right)^{th} of initial value and temperature is raised to 327∘327^\circ C, then energy emitted per unit time becomes

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Answer: (a)

  1. E∝AT4E \propto A T^4.
  2. Length and breadth become 14\frac{1}{4}: A→A16A \to \frac{A}{16}.
  3. T:300 K→600 KT: 300\text{ K} \to 600\text{ K}, factor 1616.
  4. E′=1616E=EE' = \frac{16}{16}E = E, so the answer is (a).
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