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MHT CET 2024 (10 May, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2024 (10 May, Shift 1)

Q62MHT CET 2024 · 10 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

A black sphere has radius $R$ whose rate of radiation is E at temperature T. If radius is made half and temperature 4 T, the rate of radiation will be

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Answer: (a)

Rate of radiation $E \propto R^2 T^4$ .
$\dfrac{E'}{E} = \left(\dfrac{1}{2}\right)^2 (4)^4 = \dfrac{256}{4} = 64$
So the answer is (a) $64E$ .

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