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JEE Main 2024 (8 Apr, Shift 2) · Spring & Elastic Energy

Spring & Elastic Energy question from JEE Main 2024 (8 Apr, Shift 2)

Q6JEE Main 2024 · 8 APR · SHIFT 2Medium

Spring & Elastic Energy

Figure

A block is simply released from the top of an inclined plane as shown in the figure above. The maximum compression in the spring when the block hits the spring is:

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Answer: (d)

  1. Height of incline top: h=10sin⁡30∘=5h = 10\sin 30^\circ = 5 m, so energy =mgh=5×10×5=250= mgh = 5 \times 10 \times 5 = 250 J.
  2. Friction on the 2 m rough patch: μmgd=0.5×50×2=50\mu mg d = 0.5 \times 50 \times 2 = 50 J.
  3. Energy given to spring: 250−50=200=12(100)x2⇒x2=4250 - 50 = 200 = \frac{1}{2}(100)x^2 \Rightarrow x^2 = 4
  4. So the answer is (d) 22 m.
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