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JEE Main 2026 (23 Jan, Shift 2) · Friction on an Incline

Friction on an Incline question from JEE Main 2026 (23 Jan, Shift 2)

Q1JEE Main 2026 · 23 JAN · SHIFT 2Medium

Friction on an Incline

A block is sliding down on an inclined plane of slope θ\theta and at an instant t=0t = 0 this block is given an upward momentum so that it starts moving up on the inclined surface with velocity uu. The distance (S)(S) travelled by the block before its velocity become zero, is ______.

(g = gravitational acceleration)

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Answer: (c)

  1. No friction coefficient is given, so the incline is taken as smooth.
  2. Moving up, deceleration =gsin⁡θ= g\sin\theta.
  3. 0=u2−2(gsin⁡θ)S⇒S=u22gsin⁡θ0 = u^2 - 2(g\sin\theta)S \Rightarrow S = \dfrac{u^2}{2g\sin\theta}
  4. So the answer is (c) u22gsin⁡θ\dfrac{u^2}{2g\sin\theta}.
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