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JEE Main 2023 (15 Apr, Shift 1) · Work by a Variable Force

Work by a Variable Force question from JEE Main 2023 (15 Apr, Shift 1)

Q7JEE Main 2023 · 15 APR · SHIFT 1Medium

Work by a Variable Force

A block of mass 10 kg10\text{ kg} is moving along xx-axis under the action of force F=5x NF = 5x\text{ N}. The work done by the force in moving the block from x=2 mx = 2\text{ m} to 4 m4\text{ m} will be __________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 30

  1. W=∫24F dx=∫245x dxW = \int_{2}^{4} F\,dx = \int_{2}^{4} 5x\,dx
  2. W=52(42−22)=52(12)W = \frac{5}{2}\left(4^2 - 2^2\right) = \frac{5}{2}(12)
  3. W=30 JW = 30\text{ J}
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