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JEE Main 2023 (1 Feb, Shift 1) · Friction Basics

Friction Basics question from JEE Main 2023 (1 Feb, Shift 1)

Q10JEE Main 2023 · 1 FEB · SHIFT 1Medium

Friction Basics

A block of mass $5\text{ kg}$ is placed at rest on a table of rough surface. Now, if a force of $30\text{ N}$ is applied in the direction parallel to surface of the table, the block slides through a distance of $50\text{ m}$ in an interval of time $10\text{ s}$ . Coefficient of kinetic friction is (given, $g = 10\text{ ms}^{-2}$ ):

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Answer: (d)

Starting from rest: $s = \tfrac{1}{2}at^2 \Rightarrow 50 = \tfrac{1}{2}a(10)^2 \Rightarrow a = 1\text{ m/s}^2$
$F - \mu mg = ma \Rightarrow 30 - \mu(50) = 5(1)$
$\mu = \dfrac{25}{50} = 0.5$
So the answer is (d) 0.50.

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