A block of mass 5 kg starting from rest is pulled up on a smooth inclined plane making an angle of 30° with horizontal with an effective acceleration of 1 m s⁻². The power delivered by the pulling force at t = 10 s from the start is ___________ W. [use g = 10 m s⁻² ] (calculate the nearest integer value) Numerical answer type. Work it out, then open the answer.

Answer: 300. Along the incline: F - mgsin 30° = ma. F = 5 × 1 + 5 × 10 × 0.5 = 30 N At t = 10 s: v = at = 10 m/s. P = Fv = 30 × 10 = 300 W

A block of mass 5 kg starting from rest is pulled up on a smooth… | JEE Main 2023 (11 Apr, Shift 2)

Q18JEE Main 2023 · 11 APR · SHIFT 2Medium

Power

A block of mass $5\text{ kg}$ starting from rest is pulled up on a smooth inclined plane making an angle of $30^\circ$ with horizontal with an effective acceleration of $1\text{ m s}^{-2}$ . The power delivered by the pulling force at $t = 10\text{ s}$ from the start is ___________ W.

[use $g = 10\text{ m s}^{-2}$ ]

(calculate the nearest integer value)

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 300

Along the incline: $F - mg\sin 30^\circ = ma$ .
$F = 5 \times 1 + 5 \times 10 \times 0.5 = 30\text{ N}$
At $t = 10$ s: $v = at = 10\text{ m/s}$ .
$P = Fv = 30 \times 10 = 300\text{ W}$

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