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NEET 2009 (AIPMT) · Spring & Elastic Energy

Spring & Elastic Energy question from NEET 2009 (AIPMT)

Q26NEET 2009 · AIPMTMedium

Spring & Elastic Energy

A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value k. The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be

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Answer: (a)

At maximum extension the block is momentarily at rest.
Loss in gravitational PE = gain in spring PE: $Mgx = \frac{1}{2}kx^2$
So the answer is (a) $x = \frac{2Mg}{k}$ .

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