A block of mass m is moving on rough horizontal surface with momentum p. The coefficient of friction between the block and surface is μ. The distance covered by block before it stops is [ g = acceleration due to gravity] (a) (2μ M² g)/(p²) (b) (p)/(2μ M g) (c) (2μ M g)/(p) (d) (p²)/(2μ M² g)

Answer: (d). Retardation a = μ g; initial speed v = p/m. v² = 2as ⇒ s = (v²)/(2μ g) = (p²)/(2μ m² g) With M = m in the options, the answer is (d) (p²)/(2μ M² g).

A block of mass m is moving on rough horizontal surface with momentum… | MHT CET 2020 (16 Oct, Shift 2)

Q20MHT CET 2020 · 16 OCT · SHIFT 2Easy

Friction Basics

A block of mass $m$ is moving on rough horizontal surface with momentum $p$ . The coefficient of friction between the block and surface is $\mu$ . The distance covered by block before it stops is [ $g =$ acceleration due to gravity]

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Answer: (d)

Retardation $a = \mu g$ ; initial speed $v = \dfrac{p}{m}$ .
$v^2 = 2as \Rightarrow s = \dfrac{v^2}{2\mu g} = \dfrac{p^2}{2\mu m^2 g}$
With $M = m$ in the options, the answer is (d) $\dfrac{p^2}{2\mu M^2 g}$ .

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