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NEET 2004 (AIPMT) · Connected Bodies & Pulleys

Connected Bodies & Pulleys question from NEET 2004 (AIPMT)

Q44NEET 2004 · AIPMTMedium

Connected Bodies & Pulleys

A block of mass m is placed on a smooth wedge of inclination $\theta$ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block will be (g is acceleration due to gravity)

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Answer: (d)

The block has only horizontal acceleration, so the vertical forces balance.
Forces on block: weight $mg$ and normal force $N$ at angle $\theta$ from vertical.
$N\cos\theta = mg \Rightarrow N = \dfrac{mg}{\cos\theta}$
So the answer is (d) $mg/\cos\theta$ .

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