Connected Bodies & Pulleys question from NEET 2018

Answer: (d)

1. On a smooth wedge only $mg$ and the normal force $N$ act on the block; the block must move with the wedge at acceleration $a$ to the right.
2. Horizontal: $N\sin\theta = ma$. Vertical: $N\cos\theta = mg$.
3. Divide: $\tan\theta = \dfrac{a}{g} \Rightarrow a = g\tan\theta$.
4. So the answer is (d).