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MHT CET 2026 (16 Apr, Shift 1) · Spring & Elastic Energy

Spring & Elastic Energy question from MHT CET 2026 (16 Apr, Shift 1)

Q1MHT CET 2026 · 16 APR · SHIFT 1Easy

Spring & Elastic Energy

A block of mass 'm' moving on a frictionless horizontal surface collides with a spring of spring constant 'K' and compresses it through a distance 'x'. The maximum momentum of the block after collision is

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Answer: (b)

Momentum is maximum just before compression starts (all energy is kinetic).
$\frac{1}{2}mv^2 = \frac{1}{2}Kx^2 \Rightarrow v = x\sqrt{K/m}$
$p = mv = x\sqrt{Km}$
So the answer is (b) $\sqrt{km}\,x$ .

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