A block of mass m slides down the plane inclined at angle 30° with an acceleration g/4. The value of coefficient of kinetic friction will be: (a) (2√(3)-1)/(2) (b) √(3)/2 (c) (1)/(2√(3)) (d) (2√(3)+1)/(2)

Answer: (c). a = g(sin θ - μcos θ) g/4 = g(1/2 - μ√(3)/2) ⇒ μ√(3)/2 = 1/4 So the answer is (c) μ = (1)/(2√(3)).

A block of mass m slides down the plane inclined at angle 30° with an… | JEE Main 2023 (29 Jan, Shift 1)

Q13JEE Main 2023 · 29 JAN · SHIFT 1Easy

Friction on an Incline

A block of mass $m$ slides down the plane inclined at angle $30^\circ$ with an acceleration $\frac{g}{4}$ . The value of coefficient of kinetic friction will be:

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Answer: (c)

$a = g(\sin\theta - \mu\cos\theta)$
$\dfrac{g}{4} = g\left(\dfrac{1}{2} - \mu\dfrac{\sqrt{3}}{2}\right) \Rightarrow \mu\dfrac{\sqrt{3}}{2} = \dfrac{1}{4}$
So the answer is (c) $\mu = \dfrac{1}{2\sqrt{3}}$ .

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