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MHT CET 2020 (19 Oct, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2020 (19 Oct, Shift 2)

Q68MHT CET 2020 · 19 OCT · SHIFT 2Medium

Simple Pendulum

A bob of a simple pendulum has mass $m$ and is oscillating with an amplitude $a$ . If the length of the pendulum is $L$ , then the maximum tension in the string is $[\cos 0^\circ = 1,\ g =$ acceleration due to gravity]

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Answer: (a)

At the mean position $T_{max} = mg + \frac{mv_{max}^2}{L}$ .
$v_{max} = a\omega = a\sqrt{g/L} \Rightarrow \frac{mv_{max}^2}{L} = mg\frac{a^2}{L^2}$ .
So the answer is (a) $mg\left[1+\left(\frac{a}{L}\right)^2\right]$ .

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