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MHT CET 2021 (21 Sep, Shift 2) · Motion Under Gravity

Motion Under Gravity question from MHT CET 2021 (21 Sep, Shift 2)

Q30MHT CET 2021 · 21 SEP · SHIFT 2Easy

Motion Under Gravity

A body at rest falls through a height 'h' with velocity 'V'. If it has to fall down further for its velocity to become three times, the distance travelled in that interval is

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Answer: (a)

From rest, $v^2 = 2gh \Rightarrow h \propto v^2$ .
Speed $3V$ needs total fall $9h$ .
Further distance $= 9h - h = 8h$
So the answer is (a) 8 h.

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