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NEET 1996 (AIPMT) · Motion Under Gravity

Motion Under Gravity question from NEET 1996 (AIPMT)

Q60NEET 1996 · AIPMTEasy

Motion Under Gravity

A body dropped from a height hh with initial velocity zero, strikes the ground with a velocity 3 m/s. Another body of same mass dropped from the same height hh with an initial velocity of 4 m/s. The final velocity of second mass, with which it strikes the ground is

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Answer: (a)

  1. First body: 32=0+2gh⇒2gh=93^2 = 0 + 2gh \Rightarrow 2gh = 9
  2. Second body: v2=u2+2gh=42+9=25v^2 = u^2 + 2gh = 4^2 + 9 = 25
  3. v=5v = 5 m/s. So the answer is (a) 5 m/s.
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