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JEE Main 2003 (AIEEE) · Energy in SHM

Energy in SHM question from JEE Main 2003 (AIEEE)

Q77JEE Main 2003 · AIEEEEasy

Energy in SHM

A body executes simple harmonic motion. The potential energy $(P.E),$ the kinetic energy $(K.E)$ and total energy $(T.E)$ are measured as a function of displacement $x.$ Which of the following statements is true?

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Answer: (a)

$KE = \frac{1}{2}k(A^2 - x^2)$ is maximum at $x = 0$ : (a) true, (c) false.
$PE = \frac{1}{2}kx^2$ is zero (minimum) at $x = 0$ : (d) false.
Total energy $\frac{1}{2}kA^2$ is constant, never zero: (b) false.
So the answer is (a).

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