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JEE Main 2023 (6 Apr, Shift 2) · Collisions

Collisions question from JEE Main 2023 (6 Apr, Shift 2)

Q3JEE Main 2023 · 6 APR · SHIFT 2Medium

Collisions

A body is dropped on ground from a height 'h1h_1 ' and after hitting the ground, it rebounds to a height 'h2h_2'. If the ratio of velocities of the body just before and after hitting ground is 4, then percentage loss in kinetic energy of the body is x4\frac{x}{4}. The value of xx is ____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 375

  1. v1v2=4⇒K2K1=116\frac{v_1}{v_2} = 4 \Rightarrow \frac{K_2}{K_1} = \frac{1}{16}
  2. Fractional loss =1−116=1516=93.75%= 1 - \frac{1}{16} = \frac{15}{16} = 93.75\%
  3. x4=93.75⇒x=375\frac{x}{4} = 93.75 \Rightarrow x = 375
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