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MHT CET 2021 (24 Sep, Shift 1) · Energy in SHM

Energy in SHM question from MHT CET 2021 (24 Sep, Shift 1)

Q61MHT CET 2021 · 24 SEP · SHIFT 1Medium

Energy in SHM

A body is executing S.H.M. under the action of force having maximum magntude 50 N50\text{ N}. When its energy is half kinetic and half potential; the magnitude of the force acting on the particle is

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Answer: (d)

  1. KE=PE⇒x=A2KE = PE \Rightarrow x = \frac{A}{\sqrt{2}}.
  2. F=kxF = kx, and Fmax=kA=50F_{max} = kA = 50 N.
  3. F=502=252F = \frac{50}{\sqrt{2}} = 25\sqrt{2} N
  4. So the answer is (d) 25225\sqrt{2} N.
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