A body is moving along a circular track of radius 100 m with velocity 20 m/s. Its tangential acceleration is 3 m/s², then its resultant acceleration will be (a) 5 m/s² (b) 4 m/s² (c) 2 m/s² (d) 3 m/s²

Answer: (a). ar = v²/r = (400)/(100) = 4 m/s ², at = 3 m/s ². a = √(4² + 3²) = 5 m/s ² So the answer is (a) 5 m/s ².

A body is moving along a circular track of radius 100 m with velocity… | MHT CET 2020 (19 Oct, Shift 2)

Q17MHT CET 2020 · 19 OCT · SHIFT 2Easy

Non-Uniform Circular Motion

A body is moving along a circular track of radius 100 m with velocity $20\text{ m/s}$ . Its tangential acceleration is $3\text{ m/s}^2$ , then its resultant acceleration will be

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Answer: (a)

$a_r = \frac{v^2}{r} = \frac{400}{100} = 4$ m/s $^2$ , $a_t = 3$ m/s $^2$ .
$a = \sqrt{4^2 + 3^2} = 5$ m/s $^2$
So the answer is (a) 5 m/s $^2$ .

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