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JEE Main 2020 (4 Sep, Shift 2) · Escape Velocity

Escape Velocity question from JEE Main 2020 (4 Sep, Shift 2)

Q57JEE Main 2020 · 4 SEP · SHIFT 2Easy

Escape Velocity

A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:

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Answer: (d)

Orbital speed at $r = R$ : $v_o = \sqrt{\frac{GM}{R}}$ .
Escape speed: $v_e = \sqrt{\frac{2GM}{R}}$ .
$\frac{v_o}{v_e} = \frac{1}{\sqrt{2}}$ .
So the answer is (d) $\frac{1}{\sqrt{2}}$ .

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