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JEE Main 2022 (29 Jun, Shift 1) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from JEE Main 2022 (29 Jun, Shift 1)

Q50JEE Main 2022 · 29 JUN · SHIFT 1Medium

Velocity & Acceleration in SHM

A body is performing simple harmonic with an amplitude of 10 cm. The velocity of the body was tripled by air jet when it is at 5 cm from its mean position. The new amplitude of vibration is x\sqrt{x} cm. The value of x is _____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 700

  1. At x=5x = 5 cm: v=ω102−52=ω75v = \omega\sqrt{10^2 - 5^2} = \omega\sqrt{75}.
  2. Tripled speed v′=3ω75v' = 3\omega\sqrt{75}, same ω\omega.
  3. A′2=x2+v′2ω2=25+9×75=700A'^2 = x^2 + \frac{v'^2}{\omega^2} = 25 + 9\times 75 = 700.
  4. A′=700A' = \sqrt{700} cm, so x=700x = 700.
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