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MHT CET 2021 (20 Sep, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2021 (20 Sep, Shift 2)

Q51MHT CET 2021 · 20 SEP · SHIFT 2Medium

Escape Velocity

A body is projected from earth's surface with thrice the escape velocity from the surface of the earth. What will be its velocity when it will escape the gravitational pull?

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Answer: (c)

  1. Energy conservation: 12mv2−GMmR=12mv∞2\tfrac12 mv^2 - \dfrac{GMm}{R} = \tfrac12 mv_\infty^2, i.e. v∞2=v2−Ve2v_\infty^2 = v^2 - V_e^2.
  2. v=3Ve⇒v∞2=9Ve2−Ve2=8Ve2v = 3V_e \Rightarrow v_\infty^2 = 9V_e^2 - V_e^2 = 8V_e^2
  3. v∞=22 Vev_\infty = 2\sqrt{2}\,V_e
  4. So the answer is (c) 22 Ve2\sqrt{2}\,V_e.
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