Student Login

Home›Chapters›Gravitation PYQs›Escape Velocity›Question 32

MHT CET 2023 (10 May, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2023 (10 May, Shift 2)

Q32MHT CET 2023 · 10 MAY · SHIFT 2Medium

Escape Velocity

A body is projected vertically from earth's surface with velocity equal to half the escape velocity. The maximum height reached by the satellite is ( $R$ = radius of earth)

Show answer and solution

Answer: (c)

For $v = Kv_e$ : $h = \frac{RK^2}{1-K^2}$ .
$K = \frac{1}{2} \Rightarrow h = \frac{R/4}{3/4}$ .
$h = \frac{R}{3}$ .
So the answer is (c) $\frac{R}{3}$ .

Report a mistake

More questions on Escape Velocity

A body (mass m) starts its motion from rest from a point distant R₀ (R₀ > R) from the…MHT CET 2023 (14 May, Shift 2)
A body of mass ' m ' kg starts falling from a distance 3R above earth's surface. When it…MHT CET 2023 (11 May, Shift 1)
A body is released from a height equal to the radius (R) of the earth. The velocity of…JEE Main 2023 (15 Apr, Shift 1)
An object is allowed to fall from a height R above the earth, where R is the radius of…JEE Main 2023 (30 Jan, Shift 2)
A space ship of mass 2 × 10⁴ kg is launched into a circular orbit close to the earth…JEE Main 2023 (11 Apr, Shift 2)
The escape velocity of a body on the earth surface is 11.2 km/s. If the same body is…NEET 2023
The escape velocity of a body on a planet 'A' is 12 kms ⁻¹. The escape velocity of the…JEE Main 2022 (29 Jun, Shift 1)
A body of mass m is projected with velocity λ ve in vertically upward direction from the…JEE Main 2022 (27 Jul, Shift 2)