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MHT CET 2023 (10 May, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2023 (10 May, Shift 2)

Q32MHT CET 2023 · 10 MAY · SHIFT 2Medium

Escape Velocity

A body is projected vertically from earth's surface with velocity equal to half the escape velocity. The maximum height reached by the satellite is ( RR = radius of earth)

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Answer: (c)

  1. For v=Kvev = Kv_e: h=RK21−K2h = \frac{RK^2}{1-K^2}.
  2. K=12⇒h=R/43/4K = \frac{1}{2} \Rightarrow h = \frac{R/4}{3/4}.
  3. h=R3h = \frac{R}{3}.
  4. So the answer is (c) R3\frac{R}{3}.
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