A body is projected vertically from earth's surface with (1/3)rd of escape velocity. The maximum height reached by the body is ( R = radius of earth) (a) R/4 (b) R/8 (c) R/9 (d) R/6

Answer: (b). For v = Kve: h = (RK²)/(1-K²). K = 1/3 ⇒ h = (R/9)/(8/9). h = R/8. So the answer is (b) R/8.

A body is projected vertically from earth's surface with (1/3)rd of… | MHT CET 2025 (20 Apr, Shift 1)

Q13MHT CET 2025 · 20 APR · SHIFT 1Medium

Escape Velocity

A body is projected vertically from earth's surface with $\left(\frac{1}{3}\right)^{\text{rd}}$ of escape velocity. The maximum height reached by the body is ( $R =$ radius of earth)

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Answer: (b)

For $v = Kv_e$ : $h = \frac{RK^2}{1-K^2}$ .
$K = \frac{1}{3} \Rightarrow h = \frac{R/9}{8/9}$ .
$h = \frac{R}{8}$ .
So the answer is (b) $\frac{R}{8}$ .

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