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MHT CET 2026 (13 Apr, Shift 1) · Escape Velocity

Escape Velocity question from MHT CET 2026 (13 Apr, Shift 1)

Q6MHT CET 2026 · 13 APR · SHIFT 1Medium

Escape Velocity

A body is projected vertically from earth's surface of radius R with velocity equal to half the escape velocity. The maximum height reached by the body is

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Answer: (a)

For $v = Kv_e$ : $h = \frac{RK^2}{1-K^2}$ .
$K = \frac{1}{2} \Rightarrow h = \frac{R/4}{3/4}$ .
$h = \frac{R}{3}$ .
So the answer is (a) $\frac{R}{3}$ .

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