Student Login

Home›Chapters›Gravitation PYQs›Escape Velocity›Question 63

MHT CET 2019 (2 May, Shift 1) · Escape Velocity

Escape Velocity question from MHT CET 2019 (2 May, Shift 1)

Q63MHT CET 2019 · 2 MAY · SHIFT 1Medium

Escape Velocity

A body is projected vertically from the surface of the earth of radius ' $R$ ' with velocity equal to half of the escape velocity. The maximum height reached by the body is

Show answer and solution

Answer: (b)

For $v = Kv_e$ : $h = \frac{RK^2}{1-K^2}$ .
$K = \frac{1}{2} \Rightarrow h = \frac{R/4}{3/4}$ .
$h = \frac{R}{3}$ .
So the answer is (b) $\frac{R}{3}$ .

Report a mistake

More questions on Escape Velocity

A satellite is revolving in a circular orbit at a height h from the earth's surface, such…JEE Main 2019 (11 Jan, Shift 1)
A satellite is moving with a constant speed v in circular orbit around the earth. An…JEE Main 2019 (10 Jan, Shift 1)
Two stars of masses 3 × 1031 kg each, and at distance 2 × 1011 m rotate in a plane about…JEE Main 2019 (10 Jan, Shift 2)
The ratio of escape velocity at earth (ve) to the escape velocity at a planet (vp) whose…NEET 2016 (Phase 1)
A satellite is revolving in a circular orbit at a height 'h' from the earth's surface…JEE Main 2016
A black hole is an object whose gravitational field is so strong that even light cannot…NEET 2014 (AIPMT)
The radius of a planet is twice the radius of earth. Both have almost equal average mass…NEET 2013
A particle of mass 'm' is kept at rest at a height 3R from the surface of earth, where…NEET 2013