A body is projected vertically upwards from earth's surface of radius ' R ' with velocity equal to 1/3rd of escape velocity. The maximum height reached by the body is (a) R/8 (b) R/6 (c) R/4 (d) R/9

Answer: (a). For v = Kve: h = (RK²)/(1-K²). K = 1/3 ⇒ h = (R/9)/(8/9). h = R/8. So the answer is (a) R/8.

A body is projected vertically upwards from earth's surface of radius… | MHT CET 2023 (12 May, Shift 2)

Q31MHT CET 2023 · 12 MAY · SHIFT 2Medium

Escape Velocity

A body is projected vertically upwards from earth's surface of radius ' $R$ ' with velocity equal to ${\frac{1}{3}}^{\text{rd}}$ of escape velocity. The maximum height reached by the body is

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Answer: (a)

For $v = Kv_e$ : $h = \frac{RK^2}{1-K^2}$ .
$K = \frac{1}{3} \Rightarrow h = \frac{R/9}{8/9}$ .
$h = \frac{R}{8}$ .
So the answer is (a) $\frac{R}{8}$ .

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Escape Velocity question from MHT CET 2023 (12 May, Shift 2)

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