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MHT CET 2023 (12 May, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2023 (12 May, Shift 2)

Q31MHT CET 2023 · 12 MAY · SHIFT 2Medium

Escape Velocity

A body is projected vertically upwards from earth's surface of radius 'RR' with velocity equal to 13rd{\frac{1}{3}}^{\text{rd}} of escape velocity. The maximum height reached by the body is

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Answer: (a)

  1. For v=Kvev = Kv_e: h=RK21−K2h = \frac{RK^2}{1-K^2}.
  2. K=13⇒h=R/98/9K = \frac{1}{3} \Rightarrow h = \frac{R/9}{8/9}.
  3. h=R8h = \frac{R}{8}.
  4. So the answer is (a) R8\frac{R}{8}.
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