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JEE Main 2022 (26 Jul, Shift 2) · Escape Velocity

Escape Velocity question from JEE Main 2022 (26 Jul, Shift 2)

Q41JEE Main 2022 · 26 JUL · SHIFT 2Medium

Escape Velocity

A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be:

(Take radius of earth =6400 km= 6400\text{ km} and g=10 m s−2g = 10\text{ m s}^{-2})

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Answer: (a)

  1. For v=Kvev = Kv_e: h=RK21−K2h = \frac{RK^2}{1-K^2}.
  2. K=13⇒h=R8K = \frac{1}{3} \Rightarrow h = \frac{R}{8}.
  3. h=64008=800h = \frac{6400}{8} = 800 km.
  4. So the answer is (a) 800 km.
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