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JEE Main 2023 (15 Apr, Shift 1) · Escape Velocity

Escape Velocity question from JEE Main 2023 (15 Apr, Shift 1)

Q35JEE Main 2023 · 15 APR · SHIFT 1Medium

Escape Velocity

A body is released from a height equal to the radius $(R)$ of the earth. The velocity of the body when it strikes the surface of the earth will be

(Given $g =$ acceleration due to gravity on the earth.)

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Answer: (d)

Released at $2R$ from the centre: $\frac{1}{2}v^2 = GM\left(\frac{1}{R} - \frac{1}{2R}\right) = \frac{GM}{2R}$ .
$v^2 = \frac{GM}{R} = gR$ .
So the answer is (d) $\sqrt{gR}$ .

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